Simplified module_has_submodule on Python >= 3.3.

from __future__ import absolute_import  # Avoid importing `importlib` from this package.

import copy

import imp

from importlib import import_module

import os

import sys

                raise

if sys.version_info[:2] >= (3, 3):

    if sys.version_info[:2] >= (3, 4):

        from importlib.util import find_spec as importlib_find

    else:

        from importlib import find_loader as importlib_find

    def module_has_submodule(package, module_name):

        """See if 'module' is in 'package'."""

        try:

            package_name = package.__name__

            package_path = package.__path__

        except AttributeError:

            # package isn't a package.

            return False

        full_module_name = package_name + '.' + module_name

        return importlib_find(full_module_name, package_path) is not None

else:

    import imp

    def module_has_submodule(package, module_name):

        """See if 'module' is in 'package'."""

        name = ".".join([package.__name__, module_name])