Commit b914991b authored by Baptiste Mispelon's avatar Baptiste Mispelon
Browse files

Added more tests and documentation for dictsort. 

It's possible to use something like {{ foo|dictsort:'bar.baz' }}
but this wasn't tested or documented.
parent c349bcbd

docs/ref/templates/builtins.txt

+21 −0
Original line number Diff line number Diff line
@@ -1433,6 +1433,27 @@ then the output would be: 
        {'name': 'zed', 'age': 19},

    ]



You can also do more complicated things like::

    {{ for book in books|dictsort:"author.age"

        * {{ book.title }} ({{ book.author.name }})

    {% endfor %}



If ``books`` is:



.. code-block:: python



    [

        {'title': '1984', 'author': {'name': 'George', 'age': 45}},

        {'title': 'Timequake', 'author': {'name': 'Kurt', 'age': 75}},

        {'title': 'Alice', 'author': {'name': 'Lewis', 'age': 33}},

    ]



the the output would be::



    * Alice (Lewis)

    * 1984 (George)

    * Timequake (Kurt)



.. templatefilter:: dictsortreversed



dictsortreversed

tests/defaultfilters/tests.py

+14 −0
Original line number Diff line number Diff line
@@ -441,6 +441,20 @@ class DefaultFiltersTests(TestCase): 
        self.assertEqual(dictsort({'a': 1}, 'age'), '')

        self.assertEqual(dictsort(1, 'age'), '')



    def test_dictsort_complex_sorting_key(self):

        """

        Since dictsort uses template.Variable under the hood, it can sort

        on keys like 'foo.bar'.

        """

        data = [

            {'foo': {'bar': 1, 'baz': 'c'}},

            {'foo': {'bar': 2, 'baz': 'b'}},

            {'foo': {'bar': 3, 'baz': 'a'}},

        ]

        sorted_data = dictsort(data, 'foo.baz')



        self.assertEqual([d['foo']['bar'] for d in sorted_data], [3, 2, 1])



    def test_dictsortreversed(self):

        sorted_dicts = dictsortreversed([{'age': 23, 'name': 'Barbara-Ann'},

                                         {'age': 63, 'name': 'Ra Ra Rasputin'},