Fixed another path where imports were creating two instances of a model's

from django.db.models.options import Options, AdminOptions

from django.db import connection, backend, transaction

from django.db.models import signals

from django.db.models.loading import register_models

from django.db.models.loading import register_models, get_model

from django.dispatch import dispatcher

from django.utils.datastructures import SortedDict

from django.utils.functional import curry

        new_class._prepare()

        register_models(new_class._meta.app_label, new_class)

        return new_class

	# Because of the way imports happen (recursively), we may or may not be

	# the first class for this model to register with the framework. There

	# should only be one class for each model, so we must always return the

	# registered version.

        return get_model(new_class._meta.app_label, name)

class Model(object):

    __metaclass__ = ModelBase

    Returns the model matching the given app_label and case-insensitive model_name.

    Returns None if no model is found.

    """

    get_apps() # Run get_apps() to populate the _app_list cache. Slightly hackish.

    try:

        model_dict = _app_models[app_label]

    except KeyError: