Commit 3ab1a0c7 authored by Alex Gaynor's avatar Alex Gaynor
Browse files

[1.2.X] Converted order_with_respect_to to unittests. We have always been at...

[1.2.X] Converted order_with_respect_to to unittests.  We have always been at war with doctests.  Backport of [14043].

git-svn-id: http://code.djangoproject.com/svn/django/branches/releases/1.2.X@14044 bcc190cf-cafb-0310-a4f2-bffc1f526a37
parent 0eb8c02c
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+1 −60
Original line number Diff line number Diff line
@@ -4,6 +4,7 @@ Tests for the order_with_respect_to Meta attribute.

from django.db import models


class Question(models.Model):
    text = models.CharField(max_length=200)

@@ -16,63 +17,3 @@ class Answer(models.Model):

    def __unicode__(self):
        return unicode(self.text)

__test__ = {'API_TESTS': """
>>> q1 = Question(text="Which Beatle starts with the letter 'R'?")
>>> q1.save()
>>> q2 = Question(text="What is your name?")
>>> q2.save()
>>> Answer(text="John", question=q1).save()
>>> Answer(text="Jonno",question=q2).save()
>>> Answer(text="Paul", question=q1).save()
>>> Answer(text="Paulo", question=q2).save()
>>> Answer(text="George", question=q1).save()
>>> Answer(text="Ringo", question=q1).save()

The answers will always be ordered in the order they were inserted.

>>> q1.answer_set.all()
[<Answer: John>, <Answer: Paul>, <Answer: George>, <Answer: Ringo>]

We can retrieve the answers related to a particular object, in the order
they were created, once we have a particular object.

>>> a1 = Answer.objects.filter(question=q1)[0]
>>> a1
<Answer: John>
>>> a2 = a1.get_next_in_order()
>>> a2
<Answer: Paul>
>>> a4 = list(Answer.objects.filter(question=q1))[-1]
>>> a4
<Answer: Ringo>
>>> a4.get_previous_in_order()
<Answer: George>

Determining (and setting) the ordering for a particular item is also possible.

>>> id_list = [o.pk for o in q1.answer_set.all()]
>>> a2.question.get_answer_order() == id_list
True

>>> a5 = Answer(text="Number five", question=q1)
>>> a5.save()

It doesn't matter which answer we use to check the order, it will always be the same.

>>> a2.question.get_answer_order() == a5.question.get_answer_order()
True

The ordering can be altered:

>>> id_list = [o.pk for o in q1.answer_set.all()]
>>> x = id_list.pop()
>>> id_list.insert(-1, x)
>>> a5.question.get_answer_order() == id_list
False
>>> a5.question.set_answer_order(id_list)
>>> q1.answer_set.all()
[<Answer: John>, <Answer: Paul>, <Answer: George>, <Answer: Number five>, <Answer: Ringo>]

"""
}
+62 −0
Original line number Diff line number Diff line
from operator import attrgetter

from django.test import TestCase

from models import Question, Answer


class OrderWithRespectToTests(TestCase):
    def test_basic(self):
        q1 = Question.objects.create(text="Which Beatle starts with the letter 'R'?")
        q2 = Question.objects.create(text="What is your name?")
        
        Answer.objects.create(text="John", question=q1)
        Answer.objects.create(text="Jonno", question=q2)
        Answer.objects.create(text="Paul", question=q1)
        Answer.objects.create(text="Paulo", question=q2)
        Answer.objects.create(text="George", question=q1)
        Answer.objects.create(text="Ringo", question=q1)
        
        # The answers will always be ordered in the order they were inserted.
        self.assertQuerysetEqual(
            q1.answer_set.all(), [
                "John", "Paul", "George", "Ringo",
            ],
            attrgetter("text"),
        )
        
        # We can retrieve the answers related to a particular object, in the
        # order they were created, once we have a particular object.
        a1 = Answer.objects.filter(question=q1)[0]
        self.assertEqual(a1.text, "John")
        a2 = a1.get_next_in_order()
        self.assertEqual(a2.text, "Paul")
        a4 = list(Answer.objects.filter(question=q1))[-1]
        self.assertEqual(a4.text, "Ringo")
        self.assertEqual(a4.get_previous_in_order().text, "George")
        
        # Determining (and setting) the ordering for a particular item is also
        # possible.
        id_list = [o.pk for o in q1.answer_set.all()]
        self.assertEqual(a2.question.get_answer_order(), id_list)
        
        a5 = Answer.objects.create(text="Number five", question=q1)
        
        # It doesn't matter which answer we use to check the order, it will
        # always be the same.
        self.assertEqual(
            a2.question.get_answer_order(), a5.question.get_answer_order()
        )
        
        # The ordering can be altered:
        id_list = [o.pk for o in q1.answer_set.all()]
        x = id_list.pop()
        id_list.insert(-1, x)
        self.assertNotEqual(a5.question.get_answer_order(), id_list)
        a5.question.set_answer_order(id_list)
        self.assertQuerysetEqual(
            q1.answer_set.all(), [
                "John", "Paul", "George", "Number five", "Ringo"
            ],
            attrgetter("text")
        )